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Mathematics, 05.10.2021 19:40 Fm610899

Glven: AE = BD; CD=CE Prove: AC = BC

1) AE = BD; CD = CE

1)

Given

2) AE = AC + CE

2) Subtraction Property of Equality

3) AC +CD= BC + CD

3)

Segment Addition Postulate

4) AC +CD= BD

4) Symmetric Property of Equality

5) BD = AC + CD

5) Segment Addition Postulate

6) BD =BC+CD

3) Transitive Property of Equality

7) AC = BC

7) Substitution Property of Equality

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Glven: AE = BD; CD=CE Prove: AC = BC

1) AE = BD; CD = CE

1)

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