A frame around a rectangular family portrait has a perimeter of 70 inches. The length of the frame is 7 inches less than twice the width. Find the length and width of the frame. Width of the frame is
inches
Length of the frame is
inches

A) 2L + 2W = 70

B) L+7 = W

B) L -W = -7

B) 2L -2W = -14 then we add equation A)

A) 2L + 2W = 70

4L = 56

Length = 14 inches

Width = 21 inches

Step-by-step explanation:

Given Perimeter= 70inches.

Lenght=7 less than twice the widthor breadth.

           = 2b-7

breadth(or width)=b

Now Permieter of rectangle= 2(l+b) [NOTE: breadtha nd width are same here so we can use with as breth.]

∴2(l+b=)70

⇒2(l+b)=70

We knwow that length=2b-7

⇒2 (2b-7+b)=70

⇒2(2b+b-7)=70

⇒2(3b-7)=70

Opening the bracket...

⇒6b-14=70

Transposing (-14) to the RHS will make it (+14)

⇒6b=70+14

⇒6b=84

Transposing 6 to the RHS...

⇒b=84/6

⇒b=14

Now we have b=14

So we need to find what the lenght is, and as we have the equation L= 2b-7 and now we also know what the value of b is so we can solve the equation to find the lenght.

⇒2b-7= Lenght

⇒2(14)-7=Lenght

⇒28-7=Lenght

⇒21=Lenght

Therfore Lenght is 21 inches and Breadth is 14 inches

the solution is 12x-6y

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94