Brahmagupta's solution to a quadratic equation of the form ax? + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6?
O x =
4(3)(6) + 42 - 4 - 2722-4 - V22 - 2
2 (3)
6
3
O x = 4(3)(4)
+62 - 6
2(3)
2/21-6-21-3
3
6
O x = 4(4)(6) + 32 - 3
2(4)
105 - 3
8
O x = 4(3)(6) – 42 +4 - 2/14+4
14 + 2
3
2 (3)
6

yes because they have the same amount of green and blur marbles.

step-by-step explanation:

bfgbh bhf gfdzf bhgfrdfgbn cvdgsytrghvn ncvhgfdtrseawa hgdrsxcvbgfrewq

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.

it would be 3 ÷by 6 because the number on each side