What is the area of the rectangular box which is 30x + 7 cm by 3× - 27 cm?

Step-by-step explanation:

given,

length = 30x + 7

width = 3x - 27

we know,

area = length × width

so, after inserting the values we got,

→ (30x + 7) (3x - 27)

→ 30x( 3x - 27 ) + 7( 3x - 27)

→ 90x² - 810x + 21x - 189

→ 90x² - 789x - 189

therefore required area of the given rectangle is 90x² - 789x - 189.

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

55/i dont know i do it for the points

step-by-step explanation: