Suppose that you have three coins: two fair coins, for which the probability of H is 0.5 and the probability of T is 0.5; and a biased coin, for which the probability of H is 0.8 and the probability of T is 0.2. You choose a coin in such a way that each coin is equally likely to be chosen. You flip the coin three times, getting H all three times. What is the probability that the coin is the biased coin

step-by-step explanation:

compare

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )