Need help on number 6 and 7 I am not good at algebra in the slightest

For #6:

I believe the answer is 1) −15x^3y^3−3x^3y^2

For # 7:

I got 3) 3

First, in order to isolate the variable "x"  you need to distribute:

13x - 2(x + 4) = 8x + 1

13x -2x - 8 = 8x + 1

Then you need to combine like terms

13x - 2x - 8 = 8x + 1

11x - 8 = 8x + 1

Add 8 to both sides

11x = 8x + 9

Subtract 8x on both sides

3x = 9

Now you can divide both sides by 3...

Thus x = 3

I'm actually taking algebra right now and I gotta admit algebra is tricky for sure. However, I think it'll get easier with practice  :D

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get