A study for the National Football League (NFL) game during a previous seasons assessed the actual playing time (the time a player was actually on the field and was involved where the football actually was). The average playing time was found to be only 10.7 minutes per game. If we assume the actual playing time follows a normal distribution with a standard deviation of 0.8 minutes, determine the probability that playing time for the next game will be between 9.8 and 11.9 minutes

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

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b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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