A sugar solution with a mass of 200 grams has a percent by mass concentration of 25%.

600 gram of Sugar and Water is present in the sugar solution.

Explanation:

Let the total amount of sugar solution be x,

Equation formed:

\begin{gathered}25\% \: of \: x = 200 \\ \frac{25}{100} \times x = 200 \\ \frac{x}{4} = 200 \\ x = 200 \times 4 = 800 \: g\end{gathered}

25%ofx=200

100

25

×x=200

4

x

=200

x=200×4=800g

Amount of sugar solution excluding mass = 800 g - 200 g = 600 g

Hence, 600 g of Sugar and Water is present in the sugar solution.

1 million brothers i have in my family

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18