Finf all the pairs of numbers that have a HCF of 30 and an LCM of 3150.

HCF=30

1,30,3,10,5,6

LCM=3150

1,3150,

Step-by-step explanation:

Pair are

30 , 3150  

90, 1050

150, 630

210 , 450

Step-by-step explanation:

Let the numbers be a and b

a = 30x  and  b=30y

HCF of a and b = 30

Product of numbers  = LCM * HCF

30x * 30y = 30 * 3150

       30xy = 3150

           xy = 3150/30 =  105    

1*105   or 3* 35    or   5 * 21    or   7 * 15  

1)  105 = 1*105  

      30xy =30*1 , 30*105 =   (30 , 3150)

2) 105 = 3 * 35

 30xy =   30*3  , 30*35    = 90 , 1050

90 , 1050

3) 150 , 630

4) 210 , 450

the answer is d on edge

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.