A school needs to buy a new notebook and desktop computers for its computer lab. The notebook computers cost $350 each, and the desktop computers cost $400 each. How much would it cost to buy 19 notebooks and 15 desktop computers? How much would it cost to buy nn notebooks and dd desktop computers?

19($350)=$6650

15($400)=$6000

Step-by-step explanation:

n($350)=$$

d($400)=$$

So the cost of the notebook computers is $6,650, and I put the equation for it

and the cost of the desktop computers is $6,000 and I put the equation for this one too.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752