An isosceles right triangle has legs of equal length if the hypotenuse is 10 cm long find the length of each leg

Since this is a right triangle, we know we have to use the Pythagorean Theorem: A² + B² = C² , where A and B = the legs of the triangle (which are shorter than the hypotenuse) and C = the hypotenuse.

In this isosceles triangle, A = B (because the legs are the same size) and C is 10cm longer than A and B.

Thus we get the following,

A = x

B = x

C = x + 10

We simply plug in these variables into the equation and solve for x:

x² + x² = (x+10)²

2x² = x² + 20x + 100

x² - 20x - 100 = 0

We solve for x by completing the square:

(x² - 20x + 100) - 100 = 100

(x-10)² -100 = 100

(x-10)² = 200

x - 10 = √(200)

x - 10 = 10 √2

x = 10 + 10√2 = 24

Finally,

A ≈ 24 (or 10 + 10√2)

B ≈ 24 (or 10 + 10√2)

C ≈ 24 + 10 ≈ 34 (or 10 + 10√2 + 10 = 20 + 10√2)

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

the bolded word " farsighted" could be replaced with visionary.