the length of one base of a trapezoid is 7mm less than twice the length of the other base. the height of the trapezoid is 12mm. the area of thr trapezoid is 48mm. find the length in millimeters of the longer base. (please show step by step)

Step-by-step explanation:

let x be the length of one base in mm

The other base will be 2x - 7 mm

I will ASSUME you mean the area is 48 mm²

Area of a trapezoid is the Average base length times height

A = ½(x + (2x - 7))h

A = ½(3x - 7)h

2A/h = 3x - 7

2A/h + 7 = 3x

x = (2A/h + 7)/3

x = 2A/3h + 7/3

x = 2(48)/3(12) + 7/3

x = 5 mm

the other length is

2(5) - 7 = 3 mm

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .