The proof shows that opposite angles of a parallelogram are congruent. Given: ABCD is a parallelogram with diagonal AC. Prove: ∠ BAD ≅ ∠ DCB What is the missing reason In this partial proof? Question 3 options: ASA Substution Angle Angle Postulate Alternate Interior Angles are Congruent

answer: the is put the 450

step-by-step explanation:

step-by-step explanation:

6

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft

4.28095238095 that is the answer