Which equation shows that the Pythagorean identity is true for 0 = 3pi/2 Select the equation that is in the form sin^2 (3pi/2) + cos^2 (3pi/2) = 1.
A 02 + (-1)² = 1
B. 02 + 12 = 1
C. (-1)2 + 12 = 1
D. 12 +02 = 1

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

1 and 0

step-by-step explanation: