Henry correctly factored 4x^(2)+5x-6 as (4x-3)(x+2). He then claimed that the zeros of that quadratic function are located at x=-(1)/(2) and x=2. Did Henry correctly find the zeros of the function?

I believe Henrey is wrong

Step-by-step explanation:

because the roots of the quadratic function are

"(x= 3/4, -2)."

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

not sure but it may be b, as i said i'm not sure.