TIME SENSITIVE I REALLY NEED HELP
Which function is continuous at x = 18?

The answer is D.

Step-by-step explanation:

a) Plugging x = 18 gets numerator 0^2/18 = 0 that not continuous.

b) Plugging x = 18 the denomiator becomes a value/0 making it undefined.

c) Plugging x = 18 gets tan(2pi) = 0/1 which is 0

d) f(x) = 36 is should be a straight lines at y =36. I think. Best option is D.

answer: i don't understand. what are the options

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)