Solve the system, using substitution. write the solution as an ordered pair (m, n). 2m-3n= 6, m= 3-2n.

2(3-2n)-3n=6
6-4n-3n=6
-7n=0
=> n=0
=> m=3-2*0=3-0=3
(m,n)=(3,0)

M=−2n+3;2m−3n=6

 Solve m=−2n+3 for m

Substitute (−2n+3) for m in 2m−3n=6

2m−3n=6

2(−2n+3)−3n=6

−7n+6=6(Simplify)

−7n+6+−6=6+−6(Add -6)

−7n=0

−7n / −7=0 / −7(Divide  by -7)

n=0

 Substitute (0) for n in m=−2n+3:

m=−2n+3

m=(−2)(0)+3

m=3(Simplify)

m=3 and n=0

So it is (3,0)