Divide and write the result in standard form: 3-i/1+5i a. 1/13 +8/13i b. -1/13+8/13i c. 1/13-8/13i d. -1/13-8/13i

We are asked to write the following fraction of complex numbers in standard form: .

Whenever we are dividing by a complex number by another complex number a+bi, to write the result in standard form, we multiply the expressions in the numerator and denominator by the conjugate of a+bi, that is a-bi:



in the numerator we distribute (3-i) to 1 and -5i, in the denominator we use the difference of squares formula , and :





D

Ithink the answer would be knew

Step 1: 6x-10=1; step 2: 6x=11