Car a began a journey from a point at 9 am, traveling at 30 mph. at 10 am car b started traveling from the same point at 40 mph in the same direction as car a. at what time will car b pass car a

Car a 30(t+1)

Car b 40t

 30(t+1) =40t

30t+30 =40t

30=10t

T = 30/10 = 3hours

9 +3 = 12 noon

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !