Solve for the variable: 3(2x+1)-5x=x+3

3(2x+1)-5x=x+3
6x+3-5x=x+3  then combine like terms
x+3=x+3
  -3    -3
x=x so x would be all real numbers

Simplify the left side.

Simplify each term.

Apply the distributive property.

3(2x)+3⋅1−5x=x+33(2x)+3⋅1-5x=x+3

Multiply 22 by 33 to get 66.6x+3⋅1−5x=x+36x+3⋅1-5x=x+3

Multiply 33 by 11 to get 33.6x+3−5x=x+36x+3-5x=x+3

Subtract 5x5x from 6x6x to get xx.x+3=x+3x+3=x+3

Move all terms containing xx to the left side of the equation.

Since xx contains the variable to solve for, move it to the left side of the equation by subtracting xx from both sides.

x+3−x=3x+3-x=3

Simplify the left side of the equation.

Subtract xx from xx to get 00.0+3=30+3=3

Add 00 and 33 to get 33.3=33=3

Since 3=33=3, the equation will always be true for any value of xx.

All real numbers