Find the equation of the line that fits the description. passes through(9,- 9) and has zero slope.

What is the slope of the line shown below?

Find the area of the region that is inside r=3cos(theta) and outside r=2-cos(theta). sketch the curves.

36x2 + 49y2 = 1,764 the foci are located at: (-√13, 0) and (√13,0) (0, -√13) and (0,√13) (-1, 0) and (1, 0)edit: the answer is (- the square root of 13, 0) and (the square root of 13, 0)