How to find the values of the six trigonometric functions for 180?

I like to imagine a triangle in place of the negative x axis of the unit circle where  the opposite side = 0, the adjacent is -1 and the hypotenuse = 1.
so sin 180 = 0/1 = 0, cos 180 = -1/1 = -1   and tan 180 = -0/-1 = 0.
Then the other ratios are csc is 1/0 = indeterminate, sec = 1/-1 = -1 and cot is indeterminate.

The vertex of the quadratic function is (1.5, -.75)

You just need to add 32 to 14 and get 46.