Iam really confused. the following is an incomplete paragraph proving that ∠wrs ≅ ∠vqt, given the information in the figure where segment uv is parallel to segment wz.: according to the given information, segment uv is parallel to segment wz while angles squ and vqt are vertical angles. angle vqt is congruent to angle squ by the vertical angles theorem. because angles squ and wrs are corresponding angles, they are congruent according to the corresponding angles postulate. finally, angle vqt is congruent to angle wrs by the which property of equality accurately completes the proof? a. reflexive b. substitution c. subtraction d. transitive

Transitive.

Step-by-step explanation:

Transitive property says: if a = b ; b = c then a = c.

So, transitive property is used to prove the equality between to variables using one in common. In this case, to prove VQT = WRS you need to considerer the common angle to use this property, which is angle SQU.

So, VQT = SQU ; SQU = WRS

Hence, VQT = WRS.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.