In triangle abc, angle a is congruent to angle c, ab= 10x-7, bc= 2x+33 and ac= 4x-6. find x

Since <A is congruent to <C , so triangle ABC is an isoceles triangle and side AB is congruent to BC.

AB = BC

Therefore, we can set up an equation as following:

10x - 7 = 2x + 33

10x - 7 - 2x = 2x + 33 -2x Subtracting 2x from each sides.

8x -7 = 33

8x - 7 + 7 = 33 + 7 Add 7 to each sides.

8x = 40

Divide each sides by 40.

So, x = 5

step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3