All tutors that are employed at a local college must take a test and must score in the top 20%. if the scores are normally distributed with a mean of 78 and a standard deviation of 5, what is the cutoff score to be hired?

To solve this problem, we use the z statistic with formula:

z = (x – u) / s

or

x = s z + u

First we find the value of z at P = top 20%

z = 0.84

So the cut-off is:

x = 5 * 0.84 + 78

x = 82.2                 (ANSWER)

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !

55/i dont know i do it for the points

step-by-step explanation: