Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. be sure to create and name the appropriate geometric figures.

Example  from  the  triangle  below.  if a  line  mn      parallel to  one  side one    of  the triangle    intersects  the  other  two  sides, then  it  divide  the  two  side  ptoportionally    if  mn//ac  then  bm/ma=bn/nctherefore  if  the line  divide  two  side  of  a  triangle    proportionally  then  it  is  parellel  to  the third  side    that  is                      if  bm/ma=bn/nc  then  mn//ac

2,4,5,8,10 are divisible by 40

The answer would be c