Line v passes through point (6, 6) and is perpendicular to the graph of y = 34x – 11. line w is parallel to line v and passes through point (–6, 10). which is the equation of line w in slope-intercept form?

Two parallel lines have the same slope.  If line w is perp. to y = 34x - 11, we must find the slope of  y = 34x - 11  and then find the negative reciprocal of that slope.  That (neg. recip.) slope will be the slope of line w.

The slope of y = 34x - 11 is 34, and the neg recip. of that is -1/34:  slope of w.

Use the point-slope form of the equation of a str. line to find the eqn. of line w:

y - 10 = (-1/34)*(x - (-6) )   =>  y - 10 = (-1/34)(x+6).  This could be rewritten in other forms if desired.

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