Oint a is located at (2, 6) and point b is located at (18, 12). what point partitions the directed line segment ab¯¯¯¯¯ into a 2: 3 ratio? 825, 825) (1012, 1012) (1139, 935) (1412, 12)

Step-by-step explanation:

We are given that

Point A is at (2,6) and  point B is at  (18,12).

We have to find the point which partitions the directed line segment AB into a ratio 2:3.

We have

Section formula:

Substitute the values in the given formula then, we get

The coordinates of point which partitions the segment AB is given by

Hence, the coordinated of the point which partitions the line segment AB =

2 x t divided by n

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm