Consider the function c(x)=(x+3) (x-5)2 what are the zeros of c(x)

The zeroes would be -3 and a double root at 5.

Step-by-step explanation:

We can find this by first expanding the function.

c(x) = (x + 3)(x - 5)^2

c(x) = (x + 3)(x - 5)(x - 5)

Then we can solve for the zeroes by setting each parenthesis equal to 0 and solving.

x + 3 = 0

x = -3

x - 5 = 0

x = 5

x - 5 = 0

x = 5

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

3/6   and 9/18

step-by-step explanation: