How do you find a vector of length 10 in the direction of vequals=left angle 3 comma negative 2 right angle3,−2?

First we look for the angle of the vector, which will be given by:
 tan (x) = (- 2/3)
 Clearing x we have:
 x = ATAN (-2/3) = - 33.69 degrees.
 Which means that the angle is 33.69 degrees measured clockwise from the x axis.
 Equivalently the angle is
 360-33.69 = 326.31 degrees
 326.31 degrees measured counterclockwise from the x axis.
 The vector is then:
 v = 10 (cos (326.31) i + sin (326.31) j)
 answer
 v = 10 (cos (326.31) i + sin (326.31) j)