Seth and karen are college students who take on different jobs for income. seth needs $750 for expenses and savings each month; karen needs $700. seth has a part-time job where he earns $7.50 per hour. he also mows lawns and earns $15 per lawn that he mows. his monthly earnings can be expressed with the equation 7.50x + 15y = 750, where x is the number of hours seth works and y is the number of lawns he mows. karen has a part-time job babysitting, where she earns $6 per hour. she also walks dogs and earns $4 per dog that she walks. her monthly earnings can be expressed with the equation 6x + 4y = 700, where x is the number of hours karen works and y is the number of dogs she walks. before you begin, decide with your partner who will work with seth's information and who will work with karen's information.

Seth : 7.50x + 15y = 75015y = -7.50x + 750y = -1/2x + 50 < == slope intercept formkaren : 6x + 4y = 7004y = -6x + 700y = - 3/2x + 175 < == slope intercept formgraph : (seth)y = -1/2x + = -1/2, y int = 50 or (0,50)so start at (0,50) and since the slope is -1/2, come down 1 space and to the right 2 that down 1 space and to the right 2 doing this. then connect ur plotted points and u have ur line.graph : (karen)y = -3/2x + = -3/2, y int is 175 or (0,175)start at (0,175) and since ur slope is -3/2, go down 3 spaces and to the right 2 that down 3 and to the right that doing this. then connect ur plotted points and u have ur line.function replace y with f(x)seth : (function notation) : f(x) = -1/2x + 50karen : (function notation) : f(x) = -3/2x + 175as far as graph, u can always go to desmos, a online graphing in ur equations and see ur graph

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