Laurine and anna are running a 3-mile race. after 5 mins , laurine has run 3/4 mile and anna has run 7/10 mile. if both ladies can keep their same pace for the remainder of the race, how many minutes ahead of laurie will anna cross the finish line ? i need it asap plzz i will give the brainliest answer

5/3 = 1/4 mile every 1 2/3 minutes

1 mile = 1 2/3 * 4 = 6 2/3 minutes

3 miles x 6 2/3 = 20 minutes total for Laurine

5/7 = 1/10 mile every 0.714 minutes

0.714 *10 = 7.14 minutes per mile

7.14*3 =  21.42 minutes total for Anna

21.42 - 20 = 1.42 minutes =  1 minute 25 seconds faster

answer is c

step-by-step explanation:

the expected value of the random variable : 0, 1 and 2

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