What is the completely factored form of the expression 16x2 + 8x + 32?

the given expression is

16 x² + 8 x + 32

= 8×2 x² + 8×1 + 8×4

= 8 × [ 2 x² + x +4]

finding the discriminant

d= b² - 4 a c

  = (1)² -4×2×4

  = 1 -32

  = -31< 0,

d< 0

so, the equation has no real root.so, the two imaginary roots are by using the formula of a quadratic equation→ ax² + bx +c=0

→

so ,16 x² + 8 x + 32= 8

the thermometer is precise but not accurate

step-by-step explanation:

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81