What is the area of the
parallelogram shown below?

select one:
a. 22 cm squared
b. 24 cm squared
c. 36 cm squared
d. 32 cm squared

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

combine all like terms then its just a 2 step equation

236 cm 16 time 12 = 192

6 times 7 = 42

192+42