Find the value of the constant k that makes the function continuous. g(x)equals=startset start 2 by 2 matrix 1st row 1st column startfraction 2 x squared minus 4 x minus 16 over x minus 4 endfraction 2nd column if x not equals 4 2nd row 1st column kx minus 16 2nd column if x equals 4 endmatrix 2x2−4x−16 x−4 if x≠4 kx−16 if x=4

You seem to have
.. g(x) = {(2x^2 -4x -16)/(x -4) . . . x ≠ 4
.. .. .. .. ..{ kx -16 . . . . . . . . . . . . . . x=4

The first expression can be simplified to
.. (2x^2 -4x -16)/(x -4) = 2(x +2)(x -4)/(x -4) = 2(x +2) . . . . x ≠ 4
At x=4, this simplified version has the value
.. 2(4 +2) = 12

To make the alternate definition of g(x) have that same value at x=4, we must have
.. k*4 -16 = 12
.. 4k = 28
,, k = 7

The constant k must be 7 for the function to be continuous at x=4.

2

No a triangle cannot be formed because when you add the two smallest number together (which would be 11) the have to be bigger than the number it is "against" ( which would be 12)