for this option, you will work individually.

you’ve worked hard in this module to become a pro at equations! now, you’ll put your skills to the test. your job is to create an equations portfolio. the format is up to you. be creative! you may use a slideshow, document, video, etc. as long as all of the parts of the project are addressed, the delivery is up to you.

your portfolio must include a minimum of the following five types of equations and solutions:

two one-step equations
two equations that contains fractions
one equation with distributive property
one equation with decimals
one real-world problem that is solved by an equation
once you have created each equation, you will solve it and show your work. pretend that you are teaching the equations to a new pre-algebra student. or you can actually teach them to a sibling or friend!

this is a total of 7 equations and solutions.

You can use the example and explanations below to make your portfolio. 

1.One-step equations are equations that you can solve in just 1 step.
For example:

a. 

To get x we use the ADDITIVE PROPERTY OF EQUALITY  by adding the same quantity to both sides of the equation to cancel out figures and leave x. To cancel out 3 in the equation, we add 3 on both sides. 



-3 + 3 = 0
4+ 3 = 7

So your new equation would be:





Let's try another one step equation:

b. 

In this example we will use another type of property that involves multiplication called MULTIPLICATIVE PROPERTY OF EQUALITY where we multiply both sides with the same quantity to cancel out the figure and leave x. In this case, the quantity on the left side of the equation that we need to cancel out is 4. So we multiply 4 on both sides of the equation. 




We can cancel out 4 and that will leave you with just x. 



2. Equations with fractions:

To do equations with fractions you need to find the lowest common denominator, remove fractions by multiplying both sides with the LCD and solving for the unknown.

For example:

a.

You can look at 6 on the right hand side as a fraction:


Get the lowest common denominator of both denominators, which is 2 and 1 in this case. The LCD of 2 and 1 is 2. Now that you know it, you will multiply both sides with the LCD.



Cancel the denominator on the LHS (Left-had side) and do the operation on the RHS (Right hand side). You will be left with 



We can use another type of method to cancel out called transposing 3 to other side of the equation. When you do that you do the opposite operation. So if three is multiplied on one side, then when I transpose it it becomes division. 

Your equation then will look like this:




b. Let's try this on a more complicated equation:



LCD of 8 and 3 is 24



Simplify the expression on the LHS and RHS of the equation an you will be left with:



Transpose 6 from the LHS to the RHS and its operation will become subtraction:



Divide both LHS and RHS by 3 to cancel out three in the LHS: 


or


3. Distributive property:

If you noticed in the last example, we had a situation where one number is beside an equation enclosed in a parenthesis specifically:

3(x + 2) 

If you see this, we use the distributive property first before moving on to solving the equation. Multiply the value that is outside the parenthesis with each number inside the parenthesis. Take note of the signs because you will consider it when multiplying. Let's use another example to do so:

3(x - 2) = 12

Distribute 3 to x and 2

3x - 6 = 12

Now you have a two-step equation:

Add 6 to both sides of the equation.

3x - 6 + 6 = 12 + 6
3x = 18

Divide both sides by 3:
3x/3 = 18/3
x = 6

4. Equations with decimals:

You can do equations with decimals as is but it is much easier if you clear the decimals first by making them into whole numbers. For example:

0.02x + 0.23 = 0.95

Notice that all decimals here are in the hundredths place, so to make them all whole numbers, you can multiply all decimals with 100 to make them whole. Take note that when you do this with one term, you have to do this for all terms to keep the statement true. 

(100)0.02x + (100)0.23 = (100)0.95
2x + 23 = 95

Now that we have our new equation, we can solve for x much easier:
2x = 95 - 23
2x = 72
2x/2 = 72/2
x = 36

REAL WORLD EXAMPLE:
The shoe that you always wanted is on sale in the department store. It costs half the original price. The shoe now costs $25, what was the original price?
Equation: