Astudent solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. what was the student's error?

sin(2x)/cos x = 2sin x*cos x/ cos x = 2 sin x = 2

sin x = 1

x = pi/2

but cos pi/2 = 0

so the given equation is indeterminate for x = pi/2

Answer with Step-by-step explanation:

We are given a equation:

Now, we will solve it

 2sinx=2

 sinx=1

all the possible values of x from 0 to π so that sinx=1 is

  x=π/2

but, cos(π/2) is indeterminate

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step-by-step explanation: