Solve this system of equations: y = x2 – 3x + 12 y = –2x + 14 4. substitute the values of x, –1 and 2, into either original equation to solve for the values of y. what are the solutions of the system of equations? one solution is (–1, ). the second solution (2, ).

One solution is (–1,  ⇒ 16).

The second solution (2,  ⇒ 10). your welcome 

(-1, 16) and (2, 10)

Step-by-step explanation:

Substituting -1 in place of x in the first equation, we have

y = (-1)²-3(-1)+12 = 1--3+12 = 1+3+12 = 4+12 = 16.

Substituting -1 in place of x in the second equation gives us

y=-2(-1)+14 = 2+14 = 16

This makes the first ordered pair (-1, 16).

Substituting 2 in place of x in the first equation gives us

y=2²-3(2)+12 = 4-6+12 = -2+12 = 10

Substituting 2 in place of x in the second equation gives us

y=-2(2)+14 = -4+14 = 10

This means the ordered pair (2, 10) is the second solution.

0.038

step-by-step explanation: