The coordinates of the vertices of quadrilateral cdef are c(6, 6), d(6, 8), e(8, 10), and f(10, 8). the figure is rotated 90° about the origin. what are the vertices of the resulting image, figure c’d’e’f’? drag numbers to complete the coordinates. numbers may be used once, more than once, or not at all.

Answer/Step-by-step explanation:

If the figure is rotated clockwise:

C'(6, -6); D'(8, -6); E'(10,-8); F'(8, -10)

If the figure is rotated counterclockwise:

C'(-6, 6); D'(-8, 6); E'(-10, 8); F'(-8, 10)

A clockwise rotation 90 degrees about the origin transforms a point (x, y) to (y, -x).

A counterclockwise rotation 90 degrees about the origin transforms a point (x, y) to (-y, x).

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

is there a picture

step-by-step explanation: