Plz pts at what point(s) do these graphs intersect? y=x^2+3x-5, y=4x+1 seth’s solution: y=x^2+3x-5 y=4x+1 x^2+3x-5=4x+1 x^2-x-6=0 (x-3) (x+2)=0 x=3 and x=-2 the graphs intersect at. (-2, 0) and (3, 0) . is seth’s solution correct? explain.

In order to find where two graphs intersect, you need to set equal to each other the two equations: y = x² + 3x - 5  y = 4x + 1therefore: x² + 3x - 5  = 4x + 1which brings to: x² - x - 6 = 0the solutions of this equation are: x₁ = -2 and x₂ = +3up to this point sam's solutions are correct.  the mistake arrives because he sets the correspondent y to 0, instead he should have substituted the values found for x in either one of the original equations: y₁ = 4·(-2) + 1 = -7as well as: y₁ = (-2)² + 3(-2) - 5 = -7similarly: y₂ = 4·(+3) + 1 = 13ory₂ = (+3)² + 3(+3) - 5 = 13therefore the graphs intersect at point (-2 , -7) and (3 , 13)

The following relation is not a function

Ithink it’s a as the answer.