30 points and brainliest answerthe function h(x)=x^2+6x+7 represents a parabola part a: rewrite the function in vertex form by completing the square. show your work part b: determine the vertex and indicate whether it is a maximum or a minimum on the graph. how do you know? part c: determine the axis of symmetry for h(x)me and if you could answer all the questions fully

Hello!!

Part A.
The given equation is:
y = x^2 + 6x + 7
By completing the square:
y = (x^2 + 6x + 9) + 7 – 9
y = (x + 3)^2 – 2
y + 2 = (x + 3)^2
 
Part B.
The vertex form of a parabola is in the form:
y – k = 4p (x – h)^2
Where (h, k) is the vertex (x, y) of the parabola.
Therefore the vertex: (-3, -2)
Since 4p = 1, a positive number, therefore the parabola opens up which makes the vertex (-3, -2) the minima of the graph.
 
Part C.
The Axis of Symmetry is the x - coordinate of the vertex which is x = - 3~Nayiah~ Hope this helps!!

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Hey bby was a good way i just got