The equation (x-7^2/64)+(y+2)^2/9=1 represents an ellipse. which points are the vertices of the ellipse? (7, 1) and (7, −5) (7, −10) and (7, 6) (10, −2) and (4, −2) (15, −2) and (−1, −2

D aka (15,-2) and (-1,-2)

Step-by-step explanation:

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Vertices of the ellipse are, (15, -2) and (-1, -2)

Step-by-step explanation:

The equation of the ellipse is,

The general equation of ellipse with centre as (h, k) is,

Comparing the given equation with the general form, we get the centre of the given ellipse at (7, -2) and a=8, b=3

The line through the foci intersects the ellipse at two points, the vertices.

We know that the coordinates of the vertices when (a>b) are,

So, vertices of the given ellipse are,

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

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step-by-step explanation if you write the statements down then i could you.