Ascientist removed a sample of 39.1 grams of a chemical from a container. the sample was 5 3/4 grams less than 3/10 of the total mass of the chemical in the container. what was the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams? show your work or explain how you got it

The first thing we must do for this case is to define variables:
 x: the total mass of the chemical in the container
 y: a sample of a chemical from a container
 We have the following equation:
 y = (3/10) x - 5 3/4
 Then, for y = 39.1 we have:
 39.1 = (3/10) x - 5 3/4
 Clearing x:
 (3/10) x = 39.1 + 5 3/4
 (3/10) x = 44.85
 x = (10/3) * (44.85)
 x = 149.5 grams
 
 the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:
 x = 149.5 grams

Find 2 numbers multiply those 2 numbers the answer will be -30 but if add them together will get 7so 10 and -3 are the two numbers10(-3) = -3010+(-3) = 7(x-3)(x+10) hope this !