Pleeaassee ! the square of a number exceeds that number by 12. what are the two possible solutions? 3 or -4 3 or 4 -3 or 4 explain if you

Let's call the number x. The square of a number would be . This is 12 more than the number itself. 12 more than the number is 12+x.

Putting this together we get
This is a quadratic equation so we set it equal to zero by subtracting x+12 from both sides. We obtain:



The left-had side factors as such:
(x-4)(x+3)=0

Since we have two expressions that when multiplied give zero either one or both equal zero. We set each equal to zero to obtain the solutions:
so x =4
and
so x=-3

The two solutions are 4 and -3

Sin(a)+cos(a)+cot(a)-1=2(csc(x)+1)