The equation of a parabola is given. y=−14x2+4x−19 what are the coordinates of the vertex of the parabola?

We know that the equation of a parabola is as:

................(Equation 1)

Where h and k are the coordinates of the vertex of the parabola which is at .

Now, The equation of the parabola given to us is:

..........(Equation 2)

Thus to find the vertex of this parabola, we will have to first convert (Equation 2) to (Equation 1) and find the corresponding value of h and k. For this we will have to complete the square and balance the equation. Let us begin:

..........(Equation 2)

Thus, and

Therefore, the coordinates of the vertex of the parabola are:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer:

what is your question that you ask

step-by-step explanation: