1.) find the value of the discriminant and the the number of real solutions of x^2-8x+7=0 2.) find the value of the discriminant and the number of real solutions of 2x^2+4x+2=0

Hi there!

When we have an equation standard form...

...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant



D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.



D = 0 and therefore we have one real solution.

~ Hope this helps you.

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Anyone can me with these answers