Ahot air balloon has just lifted off and is rising at the constant rate of 1.60 m/s. suddenly, one of the passengers realizes she has left her camera on the ground. a friend picks it up and tosses it straight upward with an initial speed of 10.2 m/s. if the passenger is 2.60 m above her friend when the camera is tossed, how much time does it take for the camera to reach her?

speed of balloon which is rising upwards with constant speed is

speed of the camera which is thrown up from the ground

the distance between camera and balloon when it is thrown from the ground

now let say after time "t" the camera is catch by her friend in the balloon

So the position of balloon and camera must be same

Solving above quadratic equation we got

So after t = 0.39 s her friend will get her camera on the balloon.

force tends to be low and long diustance masses are high

continuous conducting path for current, power supply