On earth, a bowling ball is dropped, and it falls 19.6 meters just before it hits the ground. how much time did it take the bowling ball to fall this distance?

A (acceleration) = 9.81 ms-2
s (displacement [distance vector]) = 19.6m
u (original velocity) = 0ms-1
v (final velocity) = unknown
t (time) = unknown
the calculation we use the formula s=ut+1/2at2 to determine the time:

19.6 = 0 + 4.905t2
t2=19.6÷4.905=3.9959...
t = 1.99898...
therefore, it takes roughly 2 seconds for the bowling ball to fall without air resistance.

so 2 seconds.

2. they have negligible mass.