Aball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. its position function is s(t) = –16t2 + 10t + 100. what is its velocity in ft/sec when t = 2 seconds?

All you need to know is that velocity is the derivative with respect to time of position.

Therefore: ds/dt = -32t +10

To know the velocity at t=2s you just need to plug t=2 for t in the equation above.

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