Ill give brainliestyou may either fill this out on your computer or print it out and fill it in by hand. when you have finished, submit this assignment to the acceleration lab dropbox in the ohs by the due date for full credit. total score: of 50 pointsdata: / 5 points)distance (m) average time (s)0.00 | 00.20 | 0.40 | 0.60 | 0.80 | 1.0 | height of incline = mangle ( ) of incline = length of incline = 1.0 mgraph: / 5 points)

The correct answer is antinodes

Perpendicular to the wave motion 

To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.